2x(3x^3-4x^2+x-8)=0

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Solution for 2x(3x^3-4x^2+x-8)=0 equation:


Simplifying
2x(3x3 + -4x2 + x + -8) = 0

Reorder the terms:
2x(-8 + x + -4x2 + 3x3) = 0
(-8 * 2x + x * 2x + -4x2 * 2x + 3x3 * 2x) = 0
(-16x + 2x2 + -8x3 + 6x4) = 0

Solving
-16x + 2x2 + -8x3 + 6x4 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2x'.
2x(-8 + x + -4x2 + 3x3) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(-8 + x + -4x2 + 3x3)' equal to zero and attempt to solve: Simplifying -8 + x + -4x2 + 3x3 = 0 Solving -8 + x + -4x2 + 3x3 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Solution

x = {0}

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